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Finding the image distance for a thin lens

  • physics
  • intermediate
  • 14-16

Students use 1/f = 1/u + 1/v to find where a converging lens forms an image, then say whether it is real or virtual. The five variants keep the object beyond the focal point, so every answer is a real image and the arithmetic stays clean to one decimal place.

Sample question

A converging lens has a focal length of **12 cm**. An object is placed **36 cm** from the lens. \frac{1}{f} = \frac{1}{u} + \frac{1}{v} Calculate the image distance **v** in centimetres, to one decimal place.

Answer: 18.0

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